If the quadratic equation px2-2√5px+15 0
Web24 mrt. 2024 · By equating it with the general quadratic equation we get a=p, b$ = - 2\sqrt 5 p$ and c=15. Now we will calculate its discriminant by formula ${b^2} - 4ac = 0$. \Rightarrow {\left( { - 2\sqrt 5 p} \right)^2} - 4 \times p \times 15 = 0 \\ WebIt is given that the quadratic equation `px^2-2sqrt5px+15=0` has two equal roots. ∴`D=0` ⇒`(-2sqrt5p)^2-4xxpxx15=0` ⇒`20p^2-60p=0` ⇒` 20p(p-3)=0` ⇒`p=0 or p-3=0` ⇒`p=0 or p=3` For `p=0`, we get `15=0` which is not true. ∴`p≠0` Hence, the value of p is 3.
If the quadratic equation px2-2√5px+15 0
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Web26 jun. 2024 · Given quadratic equation is, px^2 - 2√5px + 15 = 0 Comparing this equation with, ax^2 + bx + c = 0 We get, a = p b = -2√5p c = 15 So the discriminant, d = b^2 - 4ac We know that a quadratic … Web25 jan. 2024 · If the quadratic equation px^2-2√5 px+15= 0 has two equal roots, then find the value of p. CBSE 2015 KHAJA ACADEMY MATHEMATICA 6.86K subscribers Subscribe 1.2K views 1 year …
Web16 jul. 2024 · Best answer It is given that the quadratic equation px2 - 2√5 px + 15 = 0 has two equal roots For p = 0, we get 15 = 0, which is not true. ∴ p ≠ 0 Hence, the value of p … Web9 apr. 2024 · Match case Limit results 1 per page. Chapter 4: Quadratic Equations 2016 Short Answer Type Questions I [2 Marks] Question 1. If x= 2/3 and x = – 3 are roots of the quadratic equations ax 2 + lx + b = 0, find the values of a and b. Solution : Question 2. If- 5 is a root of the quadratic equation 2x 2 + px -15 = 0 and the quadratic equation p(x 2 …
Web8 sep. 2024 · we know that if the discreaminant ≥ 0 then the quadratic equation has real roots. b² - 4ac ≥ 0 4² - 4 × p × 1 ≥ 0 16 - 4p ≥ 0 - 4p ≥ - 16 multiply both sides with ( -1 ) , we get 4p ≤ 16 p ≤ 16 / 4 p ≤ 4 therefore , … Web24 mrt. 2024 · Complete step-by-step answer: We know that if in quadratic equation ax2 + bx + c = 0 when the two roots are equal then its discriminant is equal to zero I.e. b2 − …
WebTwo quadratic equations px2−2qx+p=0⋯(i) and qx2−2px+q =0⋯(ii) ∀ p,q∈R. If the roots of the equation (i) are real and unequal, then equation (ii) will have: Q. Consider two quadratic equations, px2−2qx+p=0...(i) and qx2−2px+q =0...(ii) (both p and q are real).
Web15 okt. 2024 · The roots of the quadratic equation: x = (-b ± √D)/2a, where D = b 2 – 4ac. 2. ... If the coefficient of x in the quadratic equation x 2 + bx + c =0 was taken as 17 in place of 13, its roots … schaller honda in new britainWebif the quadratic equation px2-2√5px +15=0 has two equal roots then find the value of p@ShikshaZone - YouTube #CreateWithCare @ShikshaZone @cbseclassvideos … rush most popular songsWebif the quadratic equation px2-2 root 5+15 rush motorcycle exhaustWeb14 jan. 2024 · Given quadratic equation is, px² -2√5 px + 15 = 0 Compare px² - 2√5 px+ 15 = 0 with ax²+ bx+ c = 0 a = p, b = - 2√5 p , c = 15 We know that, If the roots of the quadratic equation are equal, then it's discriminant (D) equals to zero. discriminant = 0 b² - 4ac = 0 (- 2√5 p)² - 4 x p x 15 = 0 20p² - 60p = 0 20p (p - 3) = 0 p - 3 = 0 p = 3 schaller honda service couponsWebQuadratics Formula. The formula for a quadratic equation is used to find the roots of the equation. Since quadratics have a degree equal to two, therefore there will be two solutions for the equation. Suppose ax² + bx + c = 0 is the quadratic equation, then the formula to find the roots of this equation will be: x = [-b±√ (b2-4ac)]/2a. rush motionWeblf the roots of px 2+2qx+r=0 and qx 2−2 prx+q=0 are simultaneously real, then A p=q ; r =0 B 2q= pr C pr=q 2 D pr=q Medium Solution Verified by Toppr Correct option is C) Since roots are real, ⇒(2q) 2−4pr≥0 and (2 pr) 2−4q 2≥0 4q 2≥4pr and 4pr≥4q 2 To hold above two equations simultenously ∴q 2=pr Solve any question of Quadratic Equations with:- schaller ia countyWebRoots of the equation px 2 + qx + r = 0 are equal. Formula used: When the roots of quadratic equation ax 2 + bx +c = 0 are equal the D = 0, here D = b 2 - 4ac. … schaller ia to cherokee ia