WebShow that f is differentiable at x =1, i.e., use the limit definition of the derivative to compute f ' (1) . Click HERE to see a detailed solution to problem 9. PROBLEM 10 : Assume that. … WebSep 14, 2012 · Therefore the function that represents the slope of the tangent line is undefined at x = 0. Which is another way of saying the derivative is undefined at x = 0. In other words (or really the same words, repeated) the graph does have a tangent line, but the line is vertical so its slope is undefined. So the derivative is not defined at x = 0.
How do you prove that the function f(x) = x is …
WebThe Mean Value Theorem states that if a function f is continuous on the closed interval [a,b] and differentiable on the open interval (a,b), then there exists a point c in the interval (a,b) such that f' (c) is equal to the function's average rate of change over [a,b]. WebMar 30, 2024 · Transcript [email protected]−(𝑥−1), 𝑥−1<0)┤ = { ((𝑥−1), 𝑥≥[email protected] Show More. Next: Ex 5.2, 10 Important → Ask a doubt . Chapter 5 Class 12 Continuity and Differentiability; Serial order wise; Ex 5.2. Ex 5.2, 1 Ex 5.2, 2 Ex 5.2, 3 ... swix alpine wax color chart
AP CALCULUS AB 2009 SCORING GUIDELINES (Form B)
WebConsider the piecewise functions f(x) and g(x) defined below. Suppose that the function f(x) is differentiable everywhere, and that f(x)>=g(x) for every real number x. What is then the value of a+k? f(x)={0(x−1)2(2x+1) for x≤a for x>a,g(x)={012(x−k) for x≤k for x>k; Question: Consider the piecewise functions f(x) and g(x) defined below ... WebShow that the function f(x)=∣x∣ is not differentiable at the point x=0 Easy Solution Verified by Toppr f(x)=∣x∣ ={+x,−x,x≥0x<0 f(x)={+1,−1.x≥0x<0 At x=0 Left hand derivative =−1 Right hand derivative =+1 ∴ L.H.D = R.H.D So, f(x)=∣x∣ is not differentiable at x=0. Video Explanation Was this answer helpful? 0 0 Similar questions WebShow that the following function f(x) is differentiable at x=0 : f(x)={x2sin(x1)0:x=0: ... 3. Show that the following function f ( x ) is differentiable at x = 0 : f ( x ) = { x 2 sin ( x 1 ? texas tessa